STATISTICS (LECTURE 4)
STATISTICS_CLASS 10
LESSON 4
Good Morning
We have covered the following learning outcomes so far:
Q1) If the class interval are (10 --15), (15--20), (20--25) and so
on then the value of "h" is ___
{ Hint: The class size is "h". How much is (15 -10) and (20-15) and (25-20) ?}
Q2) Calculate the values of "x" & "u" for each class interval in the following table: (make the table in the notebook)
We will practice few questions with "Missing frequencies".
Please write the following Questions as important Questions in your notebookš
Q3) Find the values of f₁ & f₂ in the following table,
if the mean is 62.8
A3)
Substituting the value of f₂ from (i)
⇒ 62.8 = [2060 + 30f₁ + 70(20 - f₁)] / 50
⇒ 62.8 × 50 = [2060 + 30f₁ + 70(20 - f₁)]
⇒ 3140 = 2060 + 30f₁ + 1400 - 70f₁
⇒ 3140 - 2060 -1400 = 30f₁ - 70f₁
⇒ -320 = -40f₁
⇒ f₁ = 8 , f₂ = 20 - 8 = 12
However if I do the same question using step deviation methodš
A4)
Good Morning and Thank you boys ! š
- Recall the different ways in which the data can be written
- Recall the measures of central tendencies
- Defined mode of the given data
- Calculate Mode of the given data
- Interpret Mode of the given data
- Calculate Class Marks of the given class intervals
- Calculate Mean of the given data using "direct method"
- Calculate Mean of the given data using "assumed mean method"
Let us go through the guidelines for the blog once again:
• The text in Red, is to be written in your register
• The text in blue is to be viewed by clicking on it
• The text in green is to be practiced for home work
TO BEGIN š
I will be able to :
Please click on ➤š
TO BEGIN š
- take your SET-A Mathematics Note Book
- Our handwriting reflects a lot about us. It will be awesome if you use good presentation and cursive hand writing. Hope you are still at it !!š
- Make a column on the right hand side, if you need to do any rough work
- Leave two lines where you finished yesterday’s work and draw a horizontal line. Recall SDG-12 (turn the leaves of your notebooks to read that!) Thank youš
- Write today's date on the line after that.
- Please write the learning outcomes as mentioned below
I will be able to :
- Calculate Mean for the grouped data using the STEP DEVIATION METHOD.
- Calculate Missing Frequencies , when the Mean is given to us.
Please click on ➤š
Q1) If the class interval are (10 --15), (15--20), (20--25) and so
on then the value of "h" is ___
{ Hint: The class size is "h". How much is (15 -10) and (20-15) and (25-20) ?}
Q2) Calculate the values of "x" & "u" for each class interval in the following table: (make the table in the notebook)
Class Intervals
|
Frequency
(fi)
|
Class Marks
(xi)
|
ui = xi - A
h
|
115 - 150
|
23
| ||
150 – 185
|
52
| ||
185 – 225
|
45
| ||
225 - 260
|
37
| ||
260 - 295
|
15
|
{ Hint: What is A ? , Recall from the concept of assumed mean , done yesterday}
Now that you have calculated (ui), you do not even need to look at your class interval column or (xi) . All the remaining calculations will just involve :
(fi) & (ui)
Please click ➤što see how !
Please click ➤što see how !
Now that you have seen how to calculate the mean using "Step deviation method",
Please use the following formula to
calculate mean using "step deviation method" in Q2 š
calculate mean using "step deviation method" in Q2 š
Are you going to start over again ? Of course NOT !! š”
Get back to where you did Q2.
You already have 4 columns there ?
Make the 5th column with heading as (fi ui)
Do the calculations for the 5th column and use the formula for "step deviation method" to calculate the mean š
We will practice few questions with "Missing frequencies".
Please write the following Questions as important Questions in your notebookš
Q3) Find the values of f₁ & f₂ in the following table,
if the mean is 62.8
A3)
Substituting the value of f₂ from (i)
⇒ 62.8 = [2060 + 30f₁ + 70(20 - f₁)] / 50
⇒ 62.8 × 50 = [2060 + 30f₁ + 70(20 - f₁)]
⇒ 3140 = 2060 + 30f₁ + 1400 - 70f₁
⇒ 3140 - 2060 -1400 = 30f₁ - 70f₁
⇒ -320 = -40f₁
⇒ f₁ = 8 , f₂ = 20 - 8 = 12
However if I do the same question using step deviation methodš
Class Intervals
|
Frequency
(fi)
|
Class Marks
(xi)
|
ui = xi - A
h
|
fiui
|
0-20
|
5
|
10
|
-3
|
-15
|
20-40
|
f1
|
30
|
-2
|
-2 f1
|
40-60
|
10
|
50
|
-1
|
-10
|
60-80
|
f2
|
70
|
0
|
0
|
80-100
|
7
|
90
|
1
|
7
|
100-120
|
8
|
110
|
2
|
16
|
Ć„f i = 50
|
Ć„ fiui = -2 -2 f1
|
f2 = 20 –f1
Mean = A + (Ć„ fiui / Ć„ f i ) × h
Ć 62.8 = 70 + [ (-2 - 2 f1) / 50] × 20
Ć [ (2 + 2 f1) / 50] × 20 = 70 – 62.8
Ć (1 + f1) × 4/5 = 7.2
Ć (1 + f1) = 7.2 × 5/4
⇒ f₁ = 8 , f₂ = 20 - 8 = 12
Q4) Find the values of 'f ' in the following table:
Class Intervals
|
Frequency
(fi)
|
11-13
|
7
|
13-15
|
6
|
15-17
|
9
|
17-19
|
15
|
19-21
|
f
|
21-23
|
5
|
23-25
|
4
|
A4)
Class Intervals
|
Frequency
(fi)
|
Class Marks
(xi)
|
ui = xi - A
h
|
fiui
|
11-13
|
7
|
12
|
-4
|
-28
|
13-15
|
6
|
14
|
-3
|
-18
|
15-17
|
9
|
16
|
-2
|
-18
|
17-19
|
15
|
18
|
-1
|
-15
|
19-21
|
f
|
20
|
0
|
0
|
21-23
|
5
|
22
|
1
|
5
|
23-25
|
4
|
24
|
2
|
8
|
Ć„f i = f + 44
|
Ć„fiui = - 66
|
Mean = A + (Ć„ fiui / Ć„ f i ) × h
Ć 18 = 20 + [- 66 / (f + 44)] × 2
Ć 18 – 20 = -132 / (f + 44)
Ć f + 44 = 66
Ć f = 22
Home Work: NCERT Ex 14.1 (Q3, 7, 8, 9)
That will be all for today !
Good Morning and Thank you boys ! š
See you in the next class on 9th April 2020 !
Take a good care of yourselves !
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