STATISTICS (LECTURE 7)
LESSON STATISTICS
Dear Students,
Good Morning !!
Yesterday we covered the following learning outcomes:
1 . Recall ,measures of central tendency.
2 .calculating Mean, Median and Mode.
Let us go through the guidelines for the blog once again:
• The text in Red, is to be written in your register
• The text in blue is to be viewed by clicking on it
• The text in green is to be practised for home work
General Instructions
• take your SET-A Mathematics Register
. Please write the learning outcomes as mentioned below:
I will be able to :
• draw a less than type ogive and find its median
• draw a more than type ogive and find its median
Cumulative
Cumulative means "how much so far".
Think of the word "accumulate" which means to gather together.
To have cumulative totals, just add up the values as you go.
So that's how to do it, add up as you go down the list and you will have cumulative totals.
What is Cumulative Frequency ?
The frequency is the number of times an event occurs within a given scenario. Cumulative frequency is defined as the running total of frequencies. It is the sum of all the previous frequencies up to the current point. It is easily understandable through a Cumulative Frequency Table.
Marks | Frequency
(No. of Students)
| Cumulative Frequency |
0 – 5 | 2 | 2 |
5 – 10 | 10 | 12 |
10 – 15 | 5 | 17 |
15 – 20 | 5 | 22 |
Cumulative Frequency Curve
Cumulative Frequency Curve

A curve that represents the cumulative frequency distribution of grouped data on a graph is called a Cumulative Frequency Curve or an Ogive. Representing cumulative frequency data on a graph is the most efficient way to understand the data and derive results.
There are two types of Cumulative Frequency Curves (or Ogives) :
- More than type Cumulative Frequency Curve
- Less than type Cumulative Frequency Curve
More Than Type Cumulative Frequency Curve
Here we use the lower limit of the classes to plot the curve.
How to plot a More than type Ogive:
- In the graph, put the lower limit on the x-axis
- Mark the cumulative frequency on the y-axis.
- Plot the points (x,y) using lower limits (x) and their corresponding Cumulative frequency (y)
- Join the points by a smooth freehand curve. It looks like an upside down S.
Less Than Type Cumulative Frequency Curve
Here we use the upper limit of the classes to plot the curve.
How to plot a Less than type Ogive:
- In the graph, put the upper limit on the x-axis
- Mark the cumulative frequency on the y-axis.
- Plot the points (x,y) using upper limits (x) and their corresponding Cumulative frequency (y)
- Join the points by a smooth freehand curve. It looks like an elongated S
CLICK THE LINK TO FIND MEDIAN FROM AN OGIVE
Now quickly answer the following questions :-
Q1. Construction of a cumulative frequency table is useful determining the
1. mean
2. mode
3. median
4. all of the above
CLASS WORK
Q3 . Draw a less than type and more than type ogive for the given table and also find the median ( from the graph ) ALSO VERIFY THE RESULT BY USING MEDIAN FORMULA
t
Classes | Frequencies |
0-10 | 12 |
10-20 | 16 |
20-30 | 17 |
30-40 | 13 |
40-50 | 11 |
50-60 | 19 |
EXERCISE 14.4 (HOME WORK)
1. The following distribution gives the daily income of 50 workers if a factory. Convert the distribution above to a less than type cumulative frequency distribution and draw its ogive.
Daily income in Rupees | 100-120 | 120-140 | 140-160 | 160-180 | 180-200 |
Number of workers | 12 | 14 | 8 | 6 | 10 |
SOLUTION 1
Convert the given distribution table to a less than type cumulative frequency distribution, and we get
Daily income | Frequency | Cumulative Frequency |
Less than 120 | 12 | 12 |
Less than 140 | 14 | 26 |
Less than 160 | 8 | 34 |
Less than 180 | 6 | 40 |
Less than 200 | 10 | 50 |
From the table plot the points corresponding to the ordered pairs such as (120, 12), (140, 26), (160, 34), (180, 40) and (200, 50) on graph paper and the plotted points are joined to get a smooth curve and the obtained curve is known as less than type ogive curve

2. During the medical check-up of 35 students of a class, their weights were recorded as follows:
Weight in kg | Number of students |
Less than 38 | 0 |
Less than 40 | 3 |
Less than 42 | 5 |
Less than 44 | 9 |
Less than 46 | 14 |
Less than 48 | 28 |
Less than 50 | 32 |
Less than 52 | 35 |
Draw a less than type ogive for the given data.
Hence obtain the median weight from the graph and verify the result by using the formula.
Solution 2:
From the given data, to represent the table in the form of graph, choose the upper limits of the class intervals are in x-axis and frequencies on y-axis by choosing the convenient scale.
Now plot the points corresponding to the ordered pairs given by (38, 0), (40, 3), (42, 5), (44, 9),(46, 14), (48, 28), (50, 32) and (52, 35) on a graph paper an join them to get a smooth curve. The curve obtained is known as less than type ogive.

Locate the point 17.5 on the y-axis and draw a line parallel to the x-axis cutting the curve at a point. From the point, draw a perpendicular line to the x-axis.
The intersection point perpendicular to x-axis is the median of the given data.
MEDIAN = 46.5
Now, to find the MEDIAN by making a table.
Class interval | Number of students(Frequency) | Cumulative Frequency |
Less than 38 | 0 | 0 |
Less than 40 | 3-0=3 | 3 |
Less than 42 | 5-3=2 | 8 |
Less than 44 | 9-5=4 | 9 |
Less than 46 | 14-9=5 | 14 |
Less than 48 | 28-14=14 | 28 |
Less than 50 | 32-28=4 | 32 |
Less than 52 | 35-22=3 | 35 |
Now the cumulative frequency just greater than
is 28 belonging to class interval 46 - 48

Median class = 46 - 48
Lower class limit (l) of median class = 46
Frequency (f) of median class = 14
Cumulative frequency (cf) of class preceding median class = 14
Class size (h) = 2

So median of this data is 46.5
Hence, value of median is verified.
3. The following tables gives production yield per hectare of wheat of 100 farms of a village.
Production Yield | 50-55 | 55-60 | 60-65 | 65-70 | 70-75 | 75-80 |
Number of farms | 2 | 8 | 12 | 24 | 38 | 16 |
Change the distribution to a more than type distribution and draw its ogive.
Solution:
Converting the given distribution to a more than type distribution, we get
Production Yield (kg/ha) | Number of farms |
More than or equal to 50 | 100 |
More than or equal to 55 | 100-2 = 98 |
More than or equal to 60 | 98-8= 90 |
More than or equal to 65 | 90-12=78 |
More than or equal to 70 | 78-24=54 |
More than or equal to 75 | 54-38 =16 |
From the table obtained draw the ogive by plotting the corresponding points where the upper limits in x-axis and the frequencies obtained in the y-axis are (50, 100), (55, 98), (60, 90), (65, 78), (70, 54) and (75, 16) on this graph paper. The graph obtained is known as more than type ogive curve.

AQAD
QUESTION
The abscissa of the point of intersection of the ‘less than type’ and of the ‘more than type’ cumulative frequency curve of grouped data gives
1. mode
2. median
3. mean 4. all of the above
That's all for today I know that this is quite a lot at once but try to cover this in the double period. Tomorrow we will do more questions on this topic and it will become clearer.
please ask me if you have doubts in the topic.
!
Good Morning and Thank you boys ! 😊
Th
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AQAD . Ans.Median
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AQAD QUESTION ANS- 2) MEDIAN
Utilise your double period and finish this topic, tomorrow's blog will give you more questions based on this chapter.
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Maam I have a doubt regarding the previous blog in class work Q1:
ReplyDeleteIn the question it is shown that n=30, so n/2= 15
therefore median class being 10-20(because 15 is b/w 10 & 20)
but x is not involved anywhere in the equation
How do we do this?
1. maam in the blog there was an eg. showing that median class depends on whether the n/2 lies b/w its Lower limit and Upper limit.
2. But in one video whose link you sent it showed that if the cf of the median class is bigger and closest to n/2 then we have to choose THAT median class
maam which one is right? 1 or 2?
please tell maam, i am very confused
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Deletejoe , plz ignore the total frequency 30 , i have given you that question without total frequency ,then someone asked me without that he is not able to solve the qn.
DeleteAs per the formula 30+[ (21 +x)/2 - (5+x)]/ 6 x 10
3 = 21 + x - 2 (5 + x)/2
6= 21 + x - 10 -2x
6= 11-x
-5 =-x
x= 5.
So modal class is 30-40
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