REAL NUMBERS (LECTURE 6)
Lesson 6
Dear Students,
Good Morning Everyone!!
Yesterday we covered the following learning outcomes:
1 recall what is Euclid's Division Lemma
2 recall what is Euclid's Division Algorithm.
3. recall difference between Euclid's Division Lemma and Euclid's Division Algorithm.
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• I will be with you on this blog from 10:30AM____ till 11:20AM____so that I can address to any queries that you may have when you go through the lesson. However, if you post any query after this, I will address to that only on the next day during the same slot.
.1. take your SET-A Mathematics Register
2. Our handwriting reflects a lot about us. It will be awesome if you use good presentation and cursive hand writing
3. Make a column on the right hand side, if you need to do any rough work
1. Leave two lines where you finished yesterday’s work and draw a horizontal line
2. Write today's date on the line after that. We need to save paper. Write the SDG – 12 Remember we contemplated on SDG-17 in yesterday’s class ? Let us be responsible global citizens. One good thing that Coronovirus is teaching us! That is be responsible global citizens.
3. Pending Queries from yesterday (if any).......
4. Please write the learning outcomes as mentioned below
I will be able to summarize:
Euclid's Division Lemma
To find HCF of two numbers using Euclid's division Algorithm
et Recall Euclid's Division Lemma
Given two positive integers 'a' and 'b', there exists a unique pair of integers q and r such that
a = b x q + r, 0 ≤ r < b Lets solve an example:-
1.Show that every positive integer is of the form 2q and that every positive odd integer is of the form 2q +1.
SOLUTION
let a be any positive integer and b = 2
Then ,by Euclid's Division Lemma , we have
a = 2q +r where q ≥ 0 and 0 ≤ r < 2
then a = 2q + r , where r = 0 , 1
When r = 0 , a = 2q + 0 => a is an even integer
When r = 1 , a = 2q + 1 => a is an odd integer .
Hence every positive even integer is of the form 2q and evevy positve odd integer is of the form 2q + 1.
Now look at the image for the solution of Ex 1.1 Q2
Que 4: Show that square of any positive interger is either the form 3m or 3m +1 for some integer m.
Now look at the image for the solution of Ex 1.1 Q5
IMPORTANT: ( Answer this question in the comment column)
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REAL NUMBERS TEST ON 01/04/2020
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Today’s lesson ends here!!
Have a good day and take care
The answer to the question is (a)3q, 3q+1, 3q+2
ReplyDeleteAniket
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ReplyDeleteGood morning mam the answer to the question is (a)3q,3q+1,3q+2
ReplyDeleteMaam the the correct answer is option (a) as 3q, 3q+1 ,3q+2 as i t is not specified that the integer is a odd or an even number. This statement will suffice all the possibilities.
ReplyDeleteYashwardhan Jha.